Drag Racing Discussions > Altereds
How much power needed to run 8.60 in a 105" nostalgia type Altered?
ChevJerico:
I'm in the early stages of deciding if it's feasible or not. Thinking of stepping up, and purchasing a roller, and build my own 392 Hemi. Trying to get an idea of cost with the Hemi. Would like it to be blown on gas or methanol for the look, but that would probably be too much power for 8.60
THE FRENCHTOWN FLYER:
The 105" w.b. is relatively inconsequential. Some 100" AA/FAs run in the sixes. What is needed is the total weight of the car and driver to give you a fairly accurate idea of how much power you will need at the rear wheels. Add about 10% for a well engineered drivetrain and that will be your crankshaft HP.
ChevJerico:
--- Quote from: THE FRENCHTOWN FLYER on January 17, 2019, 06:13:46 PM ---The 105" w.b. is relatively inconsequential. Some 100" AA/FAs run in the sixes. What is needed is the total weight of the car and driver to give you a fairly accurate idea of how much power you will need at the rear wheels. Add about 10% for a well engineered drivetrain and that will be your crankshaft HP.
--- End quote ---
Oh hey thanks, Guess I kind of worded that wrong. I'm looking for a nostalgia Altered, but I know it's a matter of weight. I'm not sure how much a 105" Altered weighs? Assuming drivetrain loss and a little extra horsepower. I'm guessing about 1750 car and driver equals about 600 horsepower. Does that sound right? Just trying to get a rough idea with a little extra power just in case.
dreracecar:
weight divided ET3 ( et x et x et) X 197.14
So if the car weighs 1750# / 636 ( 8.60 ET3) = 2.75
2.75 x 197.14 = 542 HP
ChevJerico:
--- Quote from: dreracecar on January 19, 2019, 04:48:53 PM ---weight divided ET3 ( et x et x et) X 197.14
So if the car weighs 1750# / 636 ( 8.60 ET3) = 2.75
2.75 x 197.14 = 542 HP
--- End quote ---
Hey thanks, gives me an idea of what engine and how much it will cost. Was dreaming about a 392 Hemi, but might have to settle for the run of the mill BBC,SBC.
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